1 Max Flow Min Eut Algorithm Saw Class Always Terminate Example Happen Suppose E 0 Every E Q37052769

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1. The max flow/min eut algorithm we saw in class will not always terminate. Here is an example where this can happen Suppose
b) In the algorithm seen in class, show that, for large enough, you can find a sequence of paths where the flow has values 1,1. The max flow/min eut algorithm we saw in class will not always terminate. Here is an example where this can happen Suppose I(e) -0 for every edge e, suppose u(2,1)-1, (2,3)1, (4,3)- , an ue)- otherwise. b) In the algorithm seen in class, show that, for large

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