2) The following floating-point numbers are given in base 2scientific notation. First normalize the numbers and then convertthem to packet floating-point representation.
(-)0.001101 x 2^-5
Answer
-0.001101 x 2^-5=> -0.00000001101=> 1.101 * 2^-8so, normalized value of -0.001101 x 2^-5 is -1.101 * 2^-8single precision:——————–sign bit is 1(-ve)exp bits are (127-8=119) => 01110111frac bits are 10100000000000000000000so, -0.001101 x 2^-5 in single-precision format is 1 01110111 10100000000000000000000in hexadecimal it is 0xBBD00000