3. Consider the following grammar: exprterm term_tail term, tail → add-op term term-tail ε term factor factor_tail factor-tai/> mult op factor factor-tail ε factor(expr)| id | literal add-op → + mult_op*/ Draw a syntax tree for parsing each of cdf + (a25 + 84), (a25 + 84) cdf, 84*edf + a25, a25+84*cdf, a25*84cdf. Note that a25 and cdf are identifiers and 84 is a literal. You are not asked to do the tedious parsing process
OR
OR