Python programmingpleaseee
Complete the following binary search method that returns True if a given item is found in the list items (False otherwise). It also keeps track on the number of binary search steps and record the value of the index if the item is found. Note: the argument com permits some printed comments if True. der binarysearch(self, x, com): lower o upper-self.n-1 while lowerupper: mid = lower + (upper-lower)//2 if com: print(“Step #”+str(self.-step)+” if
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