Determine the minimum number of bits you would need for memoryaddress if memoery could have up to 68 GB. Without calculator.Assume byte addressing and fully explain how you arrive theanswer
Answer
If memory is byte addressable then to address any particularbyte in 68 GB memory means that we want to uniquely represent eachbyte in 68 GB in binary format.
68 GB = 68* 230 Bytes
So to represent each byte in 68 GB address memory, number ofbits needed =
Hence total 37 bits needed to uniquely represent every byte in68 GB memory.
Please comment for any clarification.
log2(68
OR
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