The following function has multiple zeros for x between -5 and 1 (see plot below). fx)cos(2x) eo3x 1.2 0 0.4 0.2 0 -0.2 0.4 -0.6 -0.8 Create a Matlab function bisection that has two arguments (one for the initial low bound and one for the initial high bound) and will use 20 rounds of bisection to find the zero of the function above. The user will thus be able to specify the
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