PYTHON
These are the scores
scores = [25, 56, 79, 94, 99]
I’ve already found the average
average = total_scores/len(scores)
print(“Sum of all scores: ” + str(total_scores))
print(“Average: ” + str(average))
How do I make exceptions for those above the average
# use filter() to figure scores that are above average pleasehelp me write a code for inside the paranthesis
above_avg = filter()
Answer
def filter(lst): s = 0 for x in lst: s += x avg = s / len(lst) count = 0 for x in
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