Q.3 Calculate the required memory size in Mebibytes (MiB) for storing a frame in 720p if the sampling scheme Y’CpCR 42:0 is used. [Hints: There are 1280 × 720 pixels in one 720p frame. Each pixel contains three primary-colour components. Each primary-colour component requires 1 byte of memory for storage. 1 Mebibyte has 10242 bytes.] Show transcribed image text Q.3 Calculate the required memory size in Mebibytes (MiB) for storing a frame in 720p
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