Show that xz =(x +y)(x +y’)(x’ +z)
a) Using truth tables.
b) Using Boolean algebraic manipulation.
Solution
ANSWER:-
(a)
(b)
xz =(x + y)(x + y’)(x’ + z)
=(x.x + xy’ + xy + yy’)(x’ + z)
=(x + xy’ + xy + 0)(x’ + z) // (idempotent law x.x=x andcomplement law yy’=0)
=(x + x(y + y’))(x’ + z)
=(x + x(1))(x’ + z) // ( complement lawy+y’=1)
=(x)(x’ + z) //(idempotent law x+x=x)
=xx’ +xz
=0+xz // ( complement law xx’=0)
=xz
to 8 つLV 0 x,1乙 REDMI NOTE 6 PRO MI DUAL CAMERA 乙+x.