Use back substitution to solve for x,y,z in the following matrix 1 2 3 191 0 1 12 0 0 13 x-2, y–1 and Z-3 x=2, y-3 and Z-1 x–1, y–1 and Z-2 x–1, y–3 1 nzz-2 0 O 0 Show transcribed image text Use back substitution to solve for x,y,z in the following matrix 1 2 3 191 0 1 12 0 0 13 x-2, y–1 and
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