Write Function Python Counts Many Non Overlapping Occurences Substring Appear String Tried Q37154960

Write a function with Python that counts how manynon-overlapping occurences of a substring appear in a string.

I tried but it fails all tests except for one:

def count(substr,theStr):

count = start = 0
while True:
start = substr.find(theStr, start) + 1
if start < 0:
count+=1
else:
return count

Solution

def countSubStr(substr,theStr): count = 0 while True: start = theStr.find(substr) + 1 theStr = theStr[start+len(substr):] if start > 0: count+=1

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